Serlo: EN: Proofs for vector spaces

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In this chapter, we will demonstrate how to prove that a set with suitable operations forms a vector space.

General proof structure

By definition, a vector space V over a field K is a set V with two operations of addition and , of scalar multiplication, satisfying a list of axioms. These are listed in the article vector space. They are four axioms for addition and four axioms for scalar multiplication, so 8 in total.

So if we want to show that a set forms a vector space, we first have to define some operations and and then prove that the axioms are satisfied. In defining the operations, note that the sum of two vectors and the product of a scalar with a vector again give vectors from the set V, i.e., for all v,wV and λK we have that vw,λvV. This is called completeness and is an important part of the well-definedness of the operations! Then we work off the axioms in the order given within the definition.

Now we want to demonstrate the whole thing with an example. As an example we choose the polynomial space of polynomials of degree less than or equal to n (for a fixed n). We prove that those polynomials form a vector space.

Definition: polynomial space

First we need to precisely define the polynomial space, i.e., the set of our vectors.

Mathe für Nicht-Freaks: Vorlage:Definition

On this set we introduce two operations, an addition and a multiplication by scalars from K:

Mathe für Nicht-Freaks: Vorlage:Definition

We want to point out that the sums on the right-hand side of the map run again only from 0 to n. So we get again polynomials which have at most degree n and so we actually end up in K[X]n. This is important to obtain well-defined operations and acting on K[X]n.

The polynomial space is a vector space

We now want to show that polynomials indeed form a vector space:

Mathe für Nicht-Freaks: Vorlage:Satz

So we need to establish the 8 vector space axioms:

Vorlage:Liste

We will now prove each of these steps individually.

Associativity of addition

We start with the associativity of addition. This follows from the associativity of addition in K.

Mathe für Nicht-Freaks: Vorlage:Beweis

Commutativity of addition

Now follows the commutativity of addition. As above, this follows from the commutativity of addition in K:

Mathe für Nicht-Freaks: Vorlage:Beweis

Neutral element of addition

Now we have to prove that a zero exists, i.e. a neutral element with respect to addition. To do this, we must first find a candidate. There is an "obvious" one here: the zero polynomial 0=i=0n0Xi. This is indeed the neutral element of the polynomial addition:

Mathe für Nicht-Freaks: Vorlage:Beweis

Inverse with respect to addition

The next step is the existence of an additive inverse. Here again there is an obvious choice: For a f=i=0nfiXi, the additive inverse is given by g=i=0n(fi)Xi:

Mathe für Nicht-Freaks: Vorlage:Beweis

Distributive law

The proofs of the two distributive laws follow from the distributive law in K and go similarly, so we show only the second one here:

Mathe für Nicht-Freaks: Vorlage:Beweis

Associative law with respect to multiplication

Next we have to establish the associative law with respect to scalar multiplication. This follows (similarly to the first two axioms) from the associativity of multiplication in K:

Mathe für Nicht-Freaks: Vorlage:Beweis

Unit property

And finally, we have to establish the unit property below:

Mathe für Nicht-Freaks: Vorlage:Beweis

We have established all 8 vector space axioms, and hence the polynomial space (K[X]n,,) is a vector space. {{#invoke:Mathe für Nicht-Freaks/Seite|unten}}